f(-3)=3(-3)^2-2(-3)+1

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Solution for f(-3)=3(-3)^2-2(-3)+1 equation: 



f(-3)=3(-3)^2-2(-3)+1

We move all terms to the left:

f(-3)-(3(-3)^2-2(-3)+1)=0

We add all the numbers together, and all the variables

f(-3)-34=0

We multiply parentheses

-3f-34=0

We move all terms containing f to the left, all other terms to the right

-3f=34

f=34/-3

f=-11+1/3

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